David Lee Roth Impersonator Arrested on Sex Charges
A man known for pretending to be Van Halen singer David Lee Roth has been arrested on charges of having underage sex.
10 Years Ago: Van Halen Reunite With David Lee Roth
It was an epic night for Van Halen fans who had been longing for the band's original singer to reaffirm his position at the mic.
Watch David Lee Roth Perform at the Summer Spectacular Under the Stars Benefit Show
David Lee Roth is still just as comfortable as ever behind the mic.
David Lee Roth Sort of Comments on New Van Halen Book
Former Van Halen manager Noel E. Monk's new memoir of his years with the band contains plenty of backstage stories, many of them involving singer David Lee Roth.
15 Years Ago: David Lee Roth and Sammy Hagar Launch Joint Tour
David Lee Roth and Sammy Hagar did the unthinkable 15 years ago while both were estranged from Van Halen; they decided to embark on a co-headlining tour.
Michael Anthony Says Time is Right for Van Halen to Tour With Both David Lee Roth and Samm…
Michael Anthony also discussed whether David Lee Roth donated $10,000 to the fundraising team honoring his late infant grandson.
Did David Lee Roth Contribute to Michael Anthony’s Fundraising Walk?
In news that should warm the heart of every Van Halen fan, it appears that David Lee Roth has donated an impressive sum of money to Michael Anthony's upcoming fundraising walk.
Sammy Hagar Wants to Tour With David Lee Roth and Van Halen
Sammy Hagar wants to tour with Van Halen, including original singer David Lee Roth, because he believes the competition between the two frontmen would make fans “die and go to heaven.”
When Van Halen Briefly Reunited with David Lee Roth for ‘Best of Vol. I’
David Lee Roth's second stint with Van Halen began and ended when he recorded some songs for a greatest hits compilation.
That Time the Van Halen-David Lee Roth Reunion Turned to S—
Van Halen's brief mid-'90s reunion with original frontman David Lee Roth ended with a thud – or, more specifically, a scathing open letter from Roth.